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Awantika Srivastava
Subject: Chemistry
, asked on 19/8/16
explain the structureof hno3 ?
Answer
4
Arshita Langoo
Subject: Chemistry
, asked on 15/8/15
calculate the percentage of covalent character of HX having bond length=1.62 Angstrom and observed dipole moment=0.39 D
Answer
1
Mariya
Subject: Chemistry
, asked on 20/9/16
GIVE THE STATE OF HYBRIDISATION IN H
2
O
2
.
Answer
1
Mariya
Subject: Chemistry
, asked on 20/9/16
THE HYBRID ORBITAL WITH MORE p-CHARACTER ARE MORE DIRECTIONAL IN CHARACTER.
PLEASE EXPLAIN WHY WE ARE CONSIDERING p-OVERLAP? IS IT BECAUSE OF THE FOLLOWING ORDER:
P-P > S-P > S-S
Answer
1
Mariya
Subject: Chemistry
, asked on 20/9/16
IN A DOUBLE BOND THERE IS ONE SIGMA AND ONE PI BOND. THE STRENGTH OF THE SIGMA BOND IS HIGHER THAN THAT OF THE PI BOND THEREFORE THE BOND ENERGY FOR DOUBLE BOND SHOULD BE LOWER THAN THAT OF SINGLE BOND. BUT IT IS NOT SO. WHY?
Answer
3
Mariya
Subject: Chemistry
, asked on 20/9/16
IN PH
3
THE CENTRAL ATOM P HAS ONE LONE PAIR AROUND IT AND THE BOND ANGLE IS 93
0
WHILE IN H
2
O THE THE OXYGEN HAS 2 LONE PAIR AROUND IT AND THE BOND ANGLE OF 104.5
0
. WHY IS IT SUCH THAT THE PHOSPHOROUS HAVING SMALLER NUMBER OF LONE HAS SMALLER BOND ANGLE WHILE THE OXYGEN HAVING THE LARGER NUMBER OF LONE PAIR HAS LARGER BOND ANGLE?
Answer
2
Mariya
Subject: Chemistry
, asked on 20/9/16
IN SHOWING THE HYBRIDISATION IN H
2
O AROUND O
2
THE 2S AND 2p
x
ARE ALSO INVOLVED IN THE HYBRIDISATION THOUGH THEY HAVE FULLY FILLED ORBITALS. WHY IS IT SO?
Answer
1
Mariya
Subject: Chemistry
, asked on 20/9/16
WHY THE SHOWING OF THE PERCENTAGE CHARACTER OF s AND p IS REQUIRED IN THE HYBRIDISATION?
Answer
1
Mariya
Subject: Chemistry
, asked on 20/9/16
WHY ONLY d
x
2
AND d
x
2
-y
2
ORBITALS ARE USED IN dsp
2
AND dsp
3
HYBRIDISATION?
Answer
2
Mariya
Subject: Chemistry
, asked on 20/9/16
ALL THE C-H BONDS ARE IDENTICAL. THIS HAS BEEN SHOWN EXPERIMENTALLY AS METHANE FORMS ONLY ONE MONOCHLOROMETHANE.
HOW CAN WE PROVE THE ABOVE STATEMENT?
Answer
1
Mariya
Subject: Chemistry
, asked on 18/9/16
HERE WHY THE FIRST STRUCTURE HAVING NEGATIVE FORMAL CHARGE ON THE OXYGEN ATOM MORE STABLE THAN THE FIRST ONE I.E. IT HAS LOWER ENERGY THAN THE FIRST ONE?
Answer
1
Mariya
Subject: Chemistry
, asked on 18/9/16
IF THE ELECTRONEGATIVITY OF THE CENTRAL ATOM DECREASES BOND ANGLE DECREASES. HOW IS THIS POSSIBLE?
Answer
1
Mariya
Subject: Chemistry
, asked on 18/9/16
WHY INTRAMOLECULAR HYDROGEN BONDING DECREASE THE MELTING AND BOILING POINT OF THE COMPOUND THOUGH THE BOND WILL BE IN THE MOLECULE ITSELF THEREFORE, THE BINDING SHOULD BECOME MORE STRONG?
Answer
1
Mariya
Subject: Chemistry
, asked on 18/9/16
WHY INTERMOLECULAR HYDROGEN BONDING INCREASES THE BOILING AND MELTING POINT AND THE SOLUBILITY IN WATER?
Answer
1
Mariya
Subject: Chemistry
, asked on 18/9/16
WHY THERE'S A HYDROGEN BONDING IN p-CHLOROPHENOL, IT HAS BEEN MENTIONED THAT THE HYDROGEN BOND CAN OCCUR ONLY BETWEEN NITROGEN, OXYGEN OR FLOURINE AND HYDROGEN.
ALSO IT IS PARTICULARLY MENTIONED THAT THOUGH CHLORINE HAS THE SAME ELECTRONEGATIVITY AS THAT OF NITROGEN, BECAUSE OF ITS LARGER SIZE.
Answer
1
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What are you looking for?
PLEASE EXPLAIN WHY WE ARE CONSIDERING p-OVERLAP? IS IT BECAUSE OF THE FOLLOWING ORDER:
P-P > S-P > S-S
HOW CAN WE PROVE THE ABOVE STATEMENT?
HERE WHY THE FIRST STRUCTURE HAVING NEGATIVE FORMAL CHARGE ON THE OXYGEN ATOM MORE STABLE THAN THE FIRST ONE I.E. IT HAS LOWER ENERGY THAN THE FIRST ONE?
ALSO IT IS PARTICULARLY MENTIONED THAT THOUGH CHLORINE HAS THE SAME ELECTRONEGATIVITY AS THAT OF NITROGEN, BECAUSE OF ITS LARGER SIZE.