1 if the points A(1,2) , B (4,q),C(p,6),D(3,5) are the vertices of a parallelogram find values of p and q - Maths - Coordinate Geometry

Question

1 if the points A(1,2) , B (4,q),C(p,6),D(3,5) are the vertices
of a parallelogram find values of p and q?
2 find the ratio in which the line segment joining points
X(1,-5),Y(-4,5)is divided by x-axis?
3 if the coordinates of points A and B are (-2,-2) and (2,-4)
find the coordinates of point X such that AX=3/7 AB and X lies on
the line segment AB
4, find the area of the triangle formed by joining the mid
points of tye sides of the triangle ABC whose vertices are A(0,-1),
B(2,1),C(0,3) and find the ratio of this area to the ratio of the
area of the given triangle

Shridhar Kaushik · Accepted Answer

Que 1 Here is the link for the answer to your query: https://www meritnation com/ask-answer/question/if-a-1-2-b-4-y-c-x-6-and-d-3-5-are-the-vertices/coordinate-geometry/1469334 Que 2 Here is the link for the answer to the similar query: https://www meritnation com/ask-answer/question/fnd-the-ratio-in-which-the-line-segment-joining-2-3-and/coordinate-geometry/1612350 Que 3 For the answer to your query, Please go to our website: http://cbse meritnation com/event/board-paper-solutions you will get your answer in the solution of All India Exam 2012 Section C(Q 26) Que 4

Since Area (A1) of âˆ†DEF isâ€“ $A_{1} = \frac{1}{2} [1 (2 - 1) + 1 (1 - 0) + 0 (0 - 2)] = \frac{1}{2} [1 + 1] = 1 Sq unit$ and Area of âˆ†ABC (A2) is â€“ $A_{2} = \frac{1}{2} [0 (2 - 3) + 2 (3 + 1) + 0 (0 - 1)] = \frac{1}{2} [0 + 8] = 4 Sq unit$ âˆ´ The ratio of area of âˆ†ABC to the are of âˆ†DEF is â€“ $\frac{A_{1}}{A_{2}} = \frac{1}{4} \Rightarrow A_{1} : A_{2} = 1 : 4$