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http://www.meritnation.com/ask-answer/question/two-opposite-angles-of-a-parallelogram-are-3x-2-and/quadrilaterals/554592

3.

Let the smallest angle be = x^{0}

As we know that in a II^{gm} opposite angles are equal

Therefore, there will be two angles with x^{0} each.

Since it is given that one angel is 24 degree less than twice the smallest angle, which gives 2x-24

Sum of all angles of parallelogram is =360

Therefore, we get

2x-24+2x-24+x+x=360

6x-48=360

6x=360+48

6x=408

x=408/6=68

Therefore, the smallest angle is of 68^{0} .

And other angle = 2x-24=2 x 68-24=112

Hence angles of the parallelogram are : 112, 112, 68, 68.

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