1)Two opposite angles of a parallelogram are (3x-2) and (50-x).Find the measure of each angle of the palallelogram.

2) IF an angle of a parallelogram is 2/3 of its adjacent angle,find the measure of the parallelogram.

3)Find measures of all the angles of the parallelogram,if one angle is 24 degree less than twice the shorter side.

#### Answers

1. Here is the link to the answer for your query.

3.

Let the smallest angle be = x^{0}

As we know that in a II^{gm} opposite angles are equal

Therefore, there will be two angles with x^{0} each.

Since it is given that one angel is 24 degree less than twice the smallest angle, which gives 2x-24

Sum of all angles of parallelogram is =360

Therefore, we get

2x-24+2x-24+x+x=360

6x-48=360

6x=360+48

6x=408

x=408/6=68

Therefore, the smallest angle is of 68^{0} .

And other angle = 2x-24=2 x 68-24=112

Hence angles of the parallelogram are : 112, 112, 68, 68.

This conversation is already closed by Expert