1. Here is the link to the answer for your query.

http://www.meritnation.com/discuss/question/554592/0/two-opposite-angles-of-a-parallelogram-are-3x-2-and-50-x-find-the-measure-of-each-angle-of-the-parallelogram

3.

Let the smallest angle be = x^{0}

As we know that in a II^{gm} opposite angles are equal

Therefore, there will be two angles with x^{0} each.

Since it is given that one angel is 24 degree less than twice the smallest angle, which gives 2x-24

Sum of all angles of parallelogram is =360

Therefore, we get

2x-24+2x-24+x+x=360

6x-48=360

6x=360+48

6x=408

x=408/6=68

Therefore, the smallest angle is of 68^{0} .

And other angle = 2x-24=2 x 68-24=112

Hence angles of the parallelogram are : 112, 112, 68, 68.