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Let the smallest angle be = x0
As we know that in a IIgm opposite angles are equal
Therefore, there will be two angles with x0 each.
Since it is given that one angel is 24 degree less than twice the smallest angle, which gives 2x-24
Sum of all angles of parallelogram is =360
Therefore, we get
Therefore, the smallest angle is of 680 .
And other angle = 2x-24=2 x 68-24=112
Hence angles of the parallelogram are : 112, 112, 68, 68.