10.125+1.5y+6ysquare-8ycube

I think your question is factorize, the given expression . 0.125 + 1.5 y + 6 y^{2} + 8 y^{3} or 0.125 - 1.5 y + 6 y^{2} - 8 y^{3} Here is the solution . 0.125 + 1.5 y + 6 y^{2} + 8 y^{3} = {(0.5)}^{3} + 3 {(0.5)}^{2} (2 y) + 3 (0.5) {(2 y)}^{2} + {(2 y)}^{3} = {(0.5 + 2 y)}^{3} [a s, a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3} = {(a + b)}^{3} = (a + b) (a + b) (a + b)] = (0.5 + 2 y) (0.5 + 2 y) (0.5 + 2 y) OR 0.125 - 1.5 y + 6 y^{2} - 8 y^{3} = {(0.5)}^{3} - 3 {(0.5)}^{2} (2 y) + 3 (0.5) {(2 y)}^{2} - {(2 y)}^{3} = {(0.5 - 2 y)}^{3} [a s, a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3} = {(a - b)}^{3} = (a - b) (a - b) (a - b)] = (0.5 - 2 y) (0.5 - 2 y) (0.5 - 2 y)

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