1500 families with 2 children were selected randomly and the following data were recorded:

number of girls in a family: 0 1 2

frequency: 211 814 475

if a family is chosen at random,compute the probability that it has:

1. no girl.

2. 1 girl.

3. 2 girls.

4. at most one girl.

5. more girls than boys.

Total number of families = 475 + 814 + 211= 1500

 

1. P ( 0 girl) = 211/1500

 

2. P( 1 girl)= 814/1500

 

3. P( 2 girls)= 475/1500

 

4. P (at most 1 girl)= P (0 girl) + P ( 1 girl)

 

5. P ( more girls than boys)= P ( 2 girls)
 


 

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