1500 families with 2 children were selected randomly and the following data were recorded:
number of girls in a family: 0 1 2
frequency: 211 814 475
if a family is chosen at random,compute the probability that it has:
1. no girl.
2. 1 girl.
3. 2 girls.
4. at most one girl.
5. more girls than boys.
Total number of families = 475 + 814 + 211= 1500
1. P ( 0 girl) = 211/1500
2. P( 1 girl)= 814/1500
3. P( 2 girls)= 475/1500
4. P (at most 1 girl)= P (0 girl) + P ( 1 girl)
5. P ( more girls than boys)= P ( 2 girls)