3 nos. r to one another 2:3:4 , the sum of their cubes is 33957.Find the nos.

 Let one no. be 2x, second be 3x and fourth be 4x.

A.T.Q => 8x³ + 27x³ + 64x³ = 33957

= 99x³ = 33957

= x³ = 33957 / 99 = 343

= x = (343)^1/3 = 7

Therefore, nos. are 14, 21 and 28.