A 0.561 m solution of an unknown electrolyte depresses the freeezing point of water by 2.93 degree C.What is the Van t Hoff factor for this electrolyte? Kf for water = 1.86 kg/mol

Since, we have the formula for depression in freezing point 

$∆T_f= m \times K_f{x}_i$
Here, vant hoff factor, i  is calculated as:

$i =\frac{∆T_f}{m \times K_f}$
Now, the substitute the values to the equation and i is calculated as:


$i =\frac{2.93 K}{0.561 mol/kg\times 1.86 K kg/mol}=2.8\simeq 3$

Hence, i = 3