A and B are two alloys of gold and copper prepared by mixing metals in proportional 7:2 and 7:11 respectively. If equal quantities of alloys are melted to form a third alloy,
then find the proportion of gold and copper in C .
We have to find the composition of copper and gold in the alloy C.
A and B are two alloys of gold and copper prepared by mixing metals in proportional 7:2 and 7:11 respectively.
Let x be the amount of each of component A and alloy B melted together to form C.
Amount of gold from A = 7x/(7+2) = 7x/9
Amount of gold from B = 7x/(7+11) = 7x/18
Total gold = 7x/9 + 7x/18 = 14x/18 + 7x/18 = 21x/18
Total copper = 2x - 21x/18 = 38x/18 - 21x/18 = 15x/18
Ratio of gold and copper in C
21x/36 : 15x/36
= 21x : 15x
= 21 : 15
= 7 : 5