a battery of emf 3 volt and internal resistance r is connected in series with a resistor of 55ohms through - Physics - Electric circuits Resistance and Ohm\s law

Question

a battery of emf 3 volt and internal resistance r is connected
in series with a resistor of 55ohms through an ammeter of
resistance 1 ohm the ammeter reads 50mA calculate the value of
r

Jyoti Pant · Accepted Answer

Here total resistance R=(r+55+1)ohm

Current I=50mA= $50 \times 10^{- 3} A$

Emf V=3 volt

Now,from V=IR

$3 = 50 \times 10^{- 3} \times (r + 55 + 1) (r + 55 + 1) = \frac{3}{50 \times 10^{- 3}} = 60 r = 4 o h m$

a battery of emf 3 volt and internal resistance r is connected in series with a resistor of 55ohms through an ammeter of resistance 1 ohm . the ammeter reads 50mA . calculate the value of r