a bullet initially moving with a velocity 20m s strikes a target and comes to rest after penetrating a distance 10 cm in the target calculate the retardation caused by the target

Here,

Initial velocity, u = 20 m/s

Final velocity, v = 0

Distance travelled, s = 10 cm = 0.1 m

Now, using,

v2 = u2 + 2as

=> 0 = 202 + (2)(a)(0.1)

=> a = -2000 m/s2

This is the acceleration of the bullet. So, the retardation is = 2000 m/s2

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intial velocity of bullet (u)= 20 m/s

final velocity of bullet (v)= 0 m/s

distance travelled after hiting the target (S)= 10 cm or 0.1 m

retardation= -a

solution-->

v2= u2 +2aS

02= 202 +(2*a*0.1)

0= 400 +0.2a

-400=0.2a

a=(-400/0.2)

a=-2000 m/s2

-a=2000 m/s2

therefore, retardation= 2000 m/s2

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