a bullet of mass 20g is fired from a gun of mass 10kg with a velocity of 180 m/s - Physics - Laws Of Motion

Question

a bullet of mass 20g is fired from a gun of mass 10kg with a
velocity of 180 m/s find the velocity of recoil of the gun find the
force required to stop tye gun before it moves 20cm

Ajay Shukla · Accepted Answer

Kinetic energy bullet = (1/2)*mv2 The force will be required to stop this bullet The force must do work done equal to the kinetic energy during the displacement of 20 cm Thus $F * d = \frac{1}{2} * m v^{2} \Rightarrow F = \frac{\frac{1}{2} * m v^{2}}{d} = \frac{\frac{1}{2} * 20 * 10^{- 3} * 180 * 180}{20 * 10^{- 2}} \Rightarrow F = 1620 N e w t o n$ Let velocity of recoil of gun = v2 then using conservation of momentum $m_{1} v_{1} = m_{2} v_{2} 20 * 10^{- 3} * 180 = 10 * v_{2} v_{2} = 0 360 m / s$

a bullet of mass 20g is fired from a gun of mass 10kg with a velocity of 180 m/s .find the velocity of recoil of the gun .find the force required to stop tye gun before it moves 20cm.