A car is moving along a straight highway with a speed of 126 kmph is bought to stop within a distance of 200m. What is the distance and the tme taken to stop the car?

Initial speed ,u = 126 km/h = 35 m/s
Distance travelled , S  = 200 m
Final speed  , V = 0  ( finally car stops)
Let a be the acceleration, and t be the time to stop car
 $$\begin{gathered} v^2-u^2=2as \\ 0-{\left(35\right)}^2=2a\left(200\right) \\ a=-\frac{1225}{400}=-3.06m/s^2 \\ v=u+at \\ 0=35m/s-3.06m/s^2\left(t\right) \\ t=11.43s \end{gathered}$$
time taken to stop car is 11.43 seconds
distance is 200 m