- a car travels with a uniform velocity of 25 m s for 5 s the brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s find
- the distance which the car travels before the brakes are applied
- the retardation
- the distance travelled by the car after applying the brakes
Case I:
Case II
u = 15 m/s and t 2 = 10 s
2. S1 = 75 m
3. v = u + at
=> 0 = 15 + a*10
=> a = - 15/10 = 1.5 m/s2
4 After applying brake distance travelled = S2
Using s = ut + 0.5at2
=> s = 15*10+0.5*(-1.5)10
=> s = 150 - 75 = 75m.