A certain force exerted for 1.2 seconds raises the speed of an object from 1.8 ms to 4.2 ms .find the accerleration ,if mass of the object is 5.5 kg .calculate the force applied. Share with your friends Share 1 Pintu B. answered this Dear Student , Here in this case the acceleration of the object is , a=v-ut=4·2-1·81·2=2 m/s2Now the mass of the object is 5·5 kg so the applied force is ,F=ma=5·5×2=11 N Regards 1 View Full Answer