A chord of a circle is equal to the radius of a circle. Find the angle subtended by the chord at a point on the minor arc and alos at a point on the major arc.

TAKE the centre O.

let the radius be OA.

the chord AB.join OB.

take a point C ob major arc and apoint D on major arc.

join BC , AC, BD, AD.

PROOF

OA=OB=BA.(AS OB and OA are the radius of the circle and ab = oa)

so ang BOA = 60 (equilateral triangle)

then ang. BCA=30.(ang subtended at the centre ..................... in the remaining part of the circle)

then ang.BDA= 180-30 (OPP.ANG OF A CYCLIC QUADRILATERAL)

         ang. BDA= 150.