a Circle C1 is drawn having  any point P on x axis  as its  centre  and passing through  the centre of the circle C: x2+y2=1. A common  tangent  to C1, and C intersects the circle  at Q and R respectively. Then Q(x,y) always satisfies x2 = lamda, find the value of  lamda.

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Please find below the solution to the asked query:

Let the point be Ph,0. Equation of circle is x-h2+y2=r2It passes through centre of x2+y2=1 which is 0,0, hence0-h2+0=r2h2=r2Hence equation will bex-h2+y2=h2...iA tangent to a circle is perpendicular to the radius at the point of tangency, so an equation of the tangent at Q isxQ-hx+yQy=xQ-hxQ+y2Q=xQ2-hxQ+y2Q=xQ2+h2-2hxQ+hxQ-h2+y2Q=xQ-h2+yQ2+hxQ-h=h2 +hxQ-h2 Using ixQ-hx+yQy=hxQ xQ-hx+yQy-hxQ=0Since this line is also tangent to C, its distance  from the origin must be equal to the radius of C.hxQxQ-h2+yQ2=1 Radius of x2+y2=1 is 1 unithxQh2=1Square both sidesh2xQ2h2=1xQ2=1λ=1

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