A coil develops heat of 800 cal/sec when 20 volts is applied across its ends The resistance of the - Physics - Physical World

Question

A coil develops heat of 800 cal/sec when 20 volts is applied
across its ends The resistance of the coil is (1 cal = 4 2
joule)

Kumar Prabhat · Accepted Answer

Heat = 800 cal/s
800×4 2 jH=V2R R=V2H = 202800×4 2 = 0 12 Ω

A coil develops heat of 800 cal/sec when 20 volts is applied across its ends. The resistance of the coil is (1 cal = 4.2 joule)