A Copper-silver cell is set up The copper ion concentration is 0 10(M) The concentration of Silveer ions - Chemistry -

Question

A Copper-silver cell is set up The copper ion concentration is 0
10(M) The concentration of Silveer ions is not known The cell
potential was found to be 0 422 v Determine the concentration of
silver ions in the cell

Apurva · Accepted Answer

Given cell: Cu(s) | Cu2+ || Ag+ | 2Ag(s)
Overall reaction: Cu(s) + 2Ag+(aq)
-----Cu2+(aq) + 2Ag(s)
E'cell = E'(Ag+/Ag) -
E'(Cu2+/Cu)
= 0 80 - 0 34
= 0 46V
There is net transfer of 2 electrons from Cu to
Ag+ ions in this reaction
Thus, n=2
According to Nernst equation,
Ecell = E'cell - 0 059/n log [Cu2+] /
[Ag+]^2
0 422 = 0 46 - 0 059/2 log [0 1] / [Ag+]^2
0 38 = 0 059/2 log [0 1] / [Ag+]^2
log [0 1] / [Ag+]^2 = 2 * 0 38 / 0 059
log [0 1] / [Ag+]^2 = 1 2881
[0 1] / [Ag+]^2 = antilog (1 2881)
[0 1] / [Ag+]^2 = 19 41
[Ag+]^2 = 0 1/19 41
[Ag+]^2 = 0 00515
[Ag+] = 0 071 mol/L

A Copper-silver cell is set up. The copper ion concentration is 0.10(M). The concentration of Silveer ions is not known. The cell potential was found to be 0.422 v. Determine the concentration of silver ions in the cell.