A parallel plate capacitor each with plate area A and separation S, is charged to a potential difference V - Physics - Electrostatic Potential And Capacitance

Question

A parallel plate capacitor each with plate area A and separation S,
is charged to a potential difference V The battery used to charge
it remains connected A dielectric slab of thickness d and
dielectric constant K is now placed between the plates What change
will take place in-

Charge on plates
Evector between the plates
Capacitance of the capacitor

Justify answer in each case

Ankur · Accepted Answer

Kindly refer to the question 3 in the link given below to get your
answer :

https://www meritnation
com/ask-answer/question/q1-the-force-of-attraction-between-2-point-charges-placed-at/electric-charges-and-fields/1810752