A piggy bank contains hundred 50 p coins,fifty 1 rupee coins,twenty 2 rupee coins &ten 5 rupee coins.If it is equally likely  that one of the coins will fall out when the bank is turned upside down,what is the probability that the coin: 1)will be a 50p coin? 2)will not be a 5 rupee coin? 3)which mathematical concept is used in above problem? 4)what is its value?  ( pls  .... i need the answer today)

Given: Number of 50 paise coins = 100

Number of 1 rupee coins = 50

Number of 2 rupee coins = 20

Number of 5 rupee coins = 10

So, total number of coins = 100 + 50 + 20 + 10 = 180

(1) Probability of 50 paise coin = Number of 50 paise coins/total number of coins = 100/180 = 5/9

(2) Probability of not 5 rupee coin = 1 - Probability of 5 rupee coin

= 1 - Number of 5 rupee coins/total number of coins = 1 - 10/180 = 1 - 1/18 = 17/18

(3) The concept used here is probability.

(4) I could not interpret which value are you taking about. Kindly be a little specific so that we can provide you meaningful help.