A ray of light passing symmetrically through a prism of RI 1.632.Find the angle of the prism if the minimum deviation is 48020/.

The expression for the refractive index in terms of minimum deviation and prism angle A is given as:
μ=sin (A+δmin2)sin(A2)We are given,μ=1.632δmin=48020'=(48+2060)0=48.30Putting these values in the expression,1.632=sin (A+48.302)sin(A2)A=59.270

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