A stone is dropped from the top of a tower 500m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g = 10 m/s sq. and speed of sound = 340 m/s

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intial velocity(u)=0

gravity=10m/s2

distance(s)=500m

let t be taken by the stone to reach surface of the water

s=ut+1/2gt^2

=500=1/2*10*t^2

t^2=500/5

=100

=t=10seconds

speed of sound in air=340m/s

time taken by sound of splash to reach the top of the tower=distance/speed of sound

=500/340

=1.47seconds

total time taken=10=1.47

=11.47seconds

ANSWER IS AVAILABLE ON THE FOLLOWING LINK ALSO

http://cbse.meritnation.com/study-online/ncert-solutions/science/8/1315/sound/a-stone-is-dropped-from-the-top-of-a-tower-5

HOWEVER THE ANSWER IS -:

Height of the tower, s = 500 m

Velocity of sound, v = 340 m s⁻¹

Acceleration due to gravity, g = 10 m s⁻²

Initial velocity of the stone, u = 0 (since the stone is initially at rest)

Time taken by the stone to fall to the base of the tower, t₁

According to the second equation of motion:

Now, time taken by the sound to reach the top from the base of the tower,

Therefore, the splash is heard at the top after time, t

Where,

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