AB is a chord to a circle with centre O. BA is extended to a point P outside the circle. A is drawn to the circle from P, which intersects the circle at T. If AB = 5 cm and AP = 4 cm, find PT.

Answer :

From given information we draw our diagram , As :

Here

AB =  5 cm
And
AP  =  4 cm
So,
PB =  PA +  AB =  4 +  5  = 9 cm
Here
AP BP is a secant and PT is a tangent , So from relationship between secant and tangent , we get

PT2 = PA × PB

PT2 = 4 × 9

PT2 = 36

PT2 = 62

PT  = 6 cm  ( Ans )

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