AB is a chord to a circle with centre O. BA is extended to a point P outside the circle. A is drawn to the circle from P, which intersects the circle at T. If AB = 5 cm and AP = 4 cm, find PT.
Answer :
From given information we draw our diagram , As :
Here
AB = 5 cm
And
AP = 4 cm
So,
PB = PA + AB = 4 + 5 = 9 cm
Here
AP BP is a secant and PT is a tangent , So from relationship between secant and tangent , we get
PT2 = PA PB
PT2 = 4 9
PT2 = 36
PT2 = 62
PT = 6 cm ( Ans )
From given information we draw our diagram , As :
Here
AB = 5 cm
And
AP = 4 cm
So,
PB = PA + AB = 4 + 5 = 9 cm
Here
AP BP is a secant and PT is a tangent , So from relationship between secant and tangent , we get
PT2 = PA PB
PT2 = 4 9
PT2 = 36
PT2 = 62
PT = 6 cm ( Ans )