ABC and BDE are two equilateral triangles such that D is the midpoint of BC AE intersects BC in - Maths - Areas of Parallelograms and Triangles

Question

ABC and BDE are two equilateral triangles such that D is the
midpoint of BC AE intersects BC in F prove that::

ar(triangle BDE)=1/4 ar(triangle ABC)
ar (triangle BDE)=1/2 ar(triangle BAE)
ar (triangle BFE)= 2ar(triangle FED)
ar(triangle FED)=1/8 ar (triangle AFC)
ar(triangle ABC)=2ar(triangle BEC)
ar(triangle BFE)=ar (triangle AFD)
ar(triangle BFE)=2ar(triangle EFD)

ramandeep.singh · Accepted Answer

Dear Student!
The solution is provided in the NCERT Solutions of this chapter
Refer to exercise 9 4, Q5

http://cbse meritnation
com/study-online/ncert-solutions/math/7/3300/areas-of-parallelograms-and-triangles/in-the-following-figure-abc-and-bde-are-two
Hope this helps you
Cheers!