ABCD is a cyclic quadrilateral and O is the centre of the circle . if angle COD = 140 and angle BAC = 40, then the value of angle BCD is equal to ?


DOC =140° {Given}DAC = 70°{the angle at the centre is twice the angle at thecircumference} CAB = 40°{given}DAC + CAB = 70°+40° = 110° = DAB Now DAB  + DCB = 180°{In cyclic quadrilateral, sum of opposite angle is 180° }DCB =  180° - 110° = 70°Hope this would have cleared your  doubt. 

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