ABCD is a parallelogram with area as 12cm2.If BD is one of the diagonals of ABCD,find ar (triangle ABD).

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Ar (ABCD) = 12cm2.
BD is a diagonal, so:-
Ar (ABD) = 1 / 2 Ar (ABCD).
(Bcz. a diagonal of a //gm divides the //gm into two congruent triangles with same area).
Therefore, Ar (ABD) = 12 / 2 = 6cm2.

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