ABCD is a rhombus.show that diagonal AC bisects angle A as well as angle C and diagonal BD bisects angle B as well as angle D?
sir/maam kindly tell me how to solve this question with proper steps?
Given:ABCD is a Rhombus
SO AB=BC=CD=AD
to prove:angle BAC=angle DAC
AND angle DCA=angle BCA
Solution: in triangles ADC and ABC
AB=AD (given)
CD=CB(given)
AC is common
so triangle ADC is congruent to triangle ABC
SO
angle BAC= angle DAC (cpct)
angle DCA= angle BCA (cpct)
HENCE PROVEN