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Subject: Math , asked on 14/1/10

ALGEBRA FORMULA FOR CLASS 10

but which one

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copy n paste this link to get ur problem solved associated with algebraic formula

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42/100

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MATHEMATICAL FORMULAE Algebra 1. (a + b)2 = a2 + 2ab + b2; a2 + b2 = (a + b)2 − 2ab 2. (a − b)2 = a2 − 2ab + b2; a2 + b2 = (a − b)2 + 2ab 3. (a + b + c)2 = a2 + b2 + c2 +2(ab +bc + ca) 4. (a + b)3 = a3 + b3 + 3ab(a + b); a3 + b3 = (a + b)3 − 3ab(a + b) 5. (a − b)3 = a3 − b3 − 3ab(a − b); a3 − b3 = (a − b)3 + 3ab(a − b) 6. a2 − b2 = (a + b)(a − b) 7. a3 − b3 = (a − b)(a2 +ab + b2) 8. a3 + b3 = (a + b)(a2 −ab + b2) 9. an − bn = (a − b)(an−1 + an−2b + an−3b2 + ··· + bn−1) 10. an = a.a.a... n times 11. am.an = am+n 12. aman = am−n if m > n = 1 if m = n = 1 an−m if m abn = an bn 16. a0 = 1 where a ∈ R,a 6= 0 17. a−n = 1an,an = 1 a−n 18. ap/q = q√ap 19. If am = an and a 6= ±1,a 6= 0 then m = n 20. If an = bn where n 6= 0, then a = ±b 21. If √x,√y are quadratic surds and if a + √x = √y, then a = 0 and x = y 22. If √x,√y are quadratic surds and if a+√x = b+√y then a = b and x = y 23. Ifa,m,n are positive real numbers and a 6= 1, then logamn = loga m+loga n 24. If a,m,n are positive real numbers, a 6= 1, then loga mn = logam−loga n 25. If a and m are positive real numbers, a 6= 1 then logamn = nloga m 26. If a,b and k are positive real numbers, b 6= 1,k 6= 1, then logb a = logk a logk b 27. logba = 1 loga b where a,b are positive real numbers, a 6= 1,b 6= 1 28. if a,m,n are positive real numbers, a 6= 1 and if loga m = logan, then m = n Typeset by AMS-TEX
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x+y=7, x=3 y=?

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hey which 1???????

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a+b

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