among the folowing which contain lowest no of atom
1)5.4g of AL
2)2g of carbon
3)0.6g of Mg
4)0.88g of  Ca

1) Molar mass of aluminium = 27 g
27 g of aluminium contains = 6.022$\times$10²³ atoms
5.4 g of aluminium contains = $\frac{6.022\times {10}^{23}}{27}\times 5.4$ =1.20$\times$10²³ atoms

2) 2 g of carbon contains = $\frac{6.022\times {10}^{23}}{12}\times 2$ =1.003$\times$10²³ atoms

3) 0.6g of Mg contains = $\frac{6.022\times {10}^{23}}{24}\times 0.6$ =0.150$\times$10²³ atoms

4) 0.88 g of  Ca contains = $\frac{6.022\times {10}^{23}}{40}\times 0.88$ =0.132$\times$10²³ atoms

5.4 g of aluminium contains max number of atoms.