an iron pipe 20 cm long has external diameter equal to 25 cm. if the thickness of the pipe is 1 cm, find the whole surface of the pipe
Let r and R be the inner and outer radius of the iron pipe respectively.
Height of the pipe, h = 20 cm.
Given, 2R = 25 cm
Thickness of the pipe = R – r
∴ R – r = 1 cm (Given)
Total surface area of the pipe
= 2 (R – r) h + 2 (R2 – r2)
= 2 (R – r) [h + (R – r)]
Thus, the total surface area of the pipe is .