an iron pipe 20 cm long has external diameter equal to 25 cm. if the thickness of the pipe is 1 cm, find the whole surface of the pipe

Let r and R be the inner and outer radius of the iron pipe respectively.

Height of the pipe, h = 20 cm.

Given, 2R = 25 cm

Thickness of the pipe = R – r

∴ R – r = 1 cm  (Given)

Total surface area of the pipe

= 2 (R – r) h + 2 (R2r2)

= 2 (R – r) [h + (R – r)]

Thus, the total surface area of the pipe is .

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OUTER DIAMETER = 25 CM

THICKNESS = 1 CM

INNER DIAMETER = 25 - 2 * 1 = 25 - 2 = 23 CM  ( BECAUSE THICKNESS IS IN THE BOTH SIDES )

RADIUS = 23 / 2 = 11 . 5 CM

HEIGHT = 20 CM

TOTAL SURFACE AREA  = 2 * 22 * 11 . 5 * ( 20 + 11 . 5 )  /  2

  = 506 * ( 31 . 5 )  /  2

 = 7969 . 5 SQUARE CM

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