Area of the largest triangle that can be inscribed in a semi-circle of radius r units is:

a) r^2 sq.units
b) 1/2 r^2 sq. units
c) 2 r^2 sq.units
d) under root 2 r^2 sq.units

 it would be a)..bcoz  one of the side will become the diameter i.e. 2r...now draw the altitude of d triangle by joining the centre of the semicircle n one of the vertices of d triangle which will be the radius of the semicircle...now area of d triangle = 1/2 x 2r x r = r^2 sq. units..

  • 7

yep i agree

  • -6

The largest triangle that can be inscribed in a semi circle of radius r units is 'an isoceles right triangle' 
so...as he said.,when we join the centre of the semicircle to the vertex of the triangle, it becomes the altitude of that triangle which is equal to the radius of the semi-circle.
and the area = 1/2 base x height
                        = 1/2 x 2r x r
                        = r^2 sq units. 
 

  • -1

 The answer is r^2......

but the concept of the largest triangle applied in the above comments is wrong.

In fact, The largest triangle will be an equilateral triangle.

  • -6
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