balance by ion electron method:P₄ +OH^-+H₂O-->PH₃+H₂PO₂ ^- Also show the steps...............

Step 1: Write the two half reactions

Oxidation half reaction : P₄àPH3

Reduction half reaction: P₄àH₂PO₂^-

Step:2

Balance the atoms other than O and H

Oxidation half reaction : P₄à4PH3

Reduction half reaction: P₄à4H₂PO₂^-

Step:3

Balance the O and H atoms using H₂O and H⁺.

Oxidation half reaction : P₄ +12H⁺à4PH3

Reduction half reaction: P₄+8H₂O à4H₂PO₂^-  +8H⁺

Step:3

Balance the charges using electrons

Oxidation half reaction : P₄ +12H⁺ +12e à4PH₃

Reduction half reaction: P₄+8H₂O à4H₂PO₂^- +8H⁺  +4e

Step: 4

Multiply the reduction half reaction with 3 and add to the oxidation half reaction in order to get the net reaction after canceling the electrons.

Oxidation half reaction : P₄ +12H⁺ +12e à4PH₃

Reduction half reaction: P₄+8H₂O à4H₂PO₂^- +8H⁺  +4e ] ×3

Net reaction:

4 P₄ +12H⁺ +24H₂Oà4PH₃ +12H₂PO₂^- +24H⁺

Or

4 P₄ +24H₂Oà4PH₃ +12H₂PO₂^- +12H⁺

Step:5

As the reaction takes place in basic medium add 12OH^- ions on both sides in order to neutralize 12H⁺.

4 P₄ +24H₂O+12OH^-à4PH₃ +12H₂PO₂^- +12H⁺+12OH^-

Or

4 P₄ +24H₂O+12OH^-à4PH₃ +12H₂PO₂^- +12H₂O

Balanced chemical equation is:

  4P₄ + 12OH^- + 12H₂O  à4PH₃ + 12H₂PO₂^-