can u please solve this... 1. calculate molarity,molality,normality of 20% h2so4 ( density =1.02g/cc) 2.a sol containing 25% urea(nh2conh2) ,25% glucose(c6h12o6) and 50% water. calculate mole fraction of each component 3.mole fraction of urea in aqua sol is 0.1. calculate molality Share with your friends Share 0 Vartika Jain answered this Dear Student, 1. 20% of acid means 20 g of acid in 100 g of solutionDensity=1.02 g/ccVolume of solution=Massdensity=1001.02=98.03 mlMolarity=Number of moles×1000Volume of solutionNumber of moles=MassMolar mass=2098=0.2040 molMolarity=0.2040×100098.03=2.08 MNormality=Molarity×BasicityFor H2SO4, basicity=2Therefore, Normality=2.08×2=4.16 NMolality, m=Molarity×1000density×1000-molar mass×molarityor, m =2.08×10001.02×1000-98×2.08=20801020-203.84=2080816.16=2.54 m2. Let the total mass of solution be 100 gMass of urea= 25 gMass of glucose=25 gMass of water=50 gnurea=massmolar mass=2560=0.41nglucose=massmolar mass=25180=0.13nwater=massmolar mass=5018=2.77Now, χurea=nureansolution=0.410.41+0.13+2.77=0.413.31=0.12 χglucose=nglucosensolution=0.130.41+0.13+2.77=0.133.31=0.03χwater=nwaternsolution=2.770.41+0.13+2.77=2.773.31=0.833. χurea=0.1and χwater=1- χurea=1-0.1=0.9Now,χurea= 0.1=nureanurea+nwater ..(i)and, χwater=0.9=nwaternurea+nwater ..(ii)Dividing the two, we get0.10.9=nureanwateror, nureanwater=19Molality,m=Number of moles of ureaMass of waterand, mass of water =Number of moles×molar mass=nwater×18Therefore, m=nureanwater×18=19×18=0.006 m 0 View Full Answer Prakhar Gupta answered this 3.relation between molality & mole fractionismolality=mole fraction*1000/(1-mole fration)*molecular wt of solvent 0 Jasmine Kaur answered this by 20/100 we can get the mass of h2so4. assume 100 to be the total mass of solution.density= mass/volume, by this volume of solution or solvent can be taken out.mass of solvent =100 - 20 0
