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 Derivation of area of triangle formula please

Dear Student!

Here is the answer to your query.

 

Let ABC be a triangle whose vertices are A (x1, y1), B (x2, y2) and C (x3, y3)

Now AL, BM and CN perpendicular from A, B, C on x - axis.

 

 

Clearly ABML, ALNC and BMNC are all trapeziums 

we know that

Area of trapezium = (Sum of parallel sides) (Distance between them)

 

Now Area of Δ ABC = Area (ABML) + Area (ALNC) – Area (BMNC)

= (BM + AL) (ML) + (AL + CN) (LN) – (BM + CN) (MN)

 

Cheers!

  • 21
View Full Answer

ar(llgm)=2ar(triangle)

(hXb)=2ar(triangle)  where h of triangle=l of parellogram

ar(triangle)=1/2(hXb)   and  base is common in both

  • -1

abe thumbs down kyon de rahe ho..

ab sab kuch main hi proof karun..

parellelogram aur rectangle in sabhi mein 2 triangle form hote hain ab un done ke areas ka sum parrellelogram ke equal to khud hi dikhana padega

  • -5

 amala wants the derivation for the one in coordinate geometry, smart boy!!!!!!!!

  • -2

 There is no derivation In class X sylibas ! That's what my sir said !!!

  • -1

but we did it in class, mam said it may come.

  • 3

 Thanks for informing looks like I have to tell my sir too THANKS FOR THE INFO 

 

you too Sir ;)

  • 3

 Isiliye tho isney poocha ..... 

  • -1
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