Derive efficiency of carnot engine and carnot theorem..
in isothermal expansion:
q1=w1
q1= 2.303 log10v2/v1 RT1
gas expands at the cost of internal energy
adiabatic process so
w2= r(t1-t2)/y -1
t1>t2
in isothermal compression:
q3=w3
q3= -RT2 2.303 log10 v3/v4
at insulating stand:
w4= -R(t1-t2)/ y -1
total work done= w1+w2+w3+w4
W= 2.303log10v2/v1 - 2.303 log10 v3/v4
W=w1-w3
W= q1-q3
n = w/q1= 1- q2/q1
n= 1-( RT2log v3/v4) /(RT1log v2/v1)
v3/v4= v2/v1 bcoz it is in isothermal n adiabatic compression as well as expansion.
n= 1-( t2/t1)