determine the oxidation number of Cr in K2Cr2O7

Dear Student,

@ lollypopply, abhishekpunethaa,

Good answers! Keep it up! Both of you have calculated the oxidation number of Cr in K2Cr2O7. Your contributions are really helpful to the users of this community.

  • -14

 Let the Oxidation number of Cr be 'x'

Now We Know that Oxidation Number of O= -2

and K= +1

According to question,

2(+1)+2(x)+7(-2)=0 ( Since a free element has 0 charge on it)

=> +2+2x-14=0

=> 2x-12=0

=> 2x= +12

=> x= +6.

Therefore the Oxidation number of Cr in the given compound is +6.

Hope it helps!!

Cheers!!!

  • 61

 Let the Oxidation number of Cr be 'x'

Now We Know that Oxidation Number of O= -2

and K= +1

According to question,

2(+1)+2(x)+7(-2)=0 ( Since a free element has 0 charge on it)

=> +2+2x-14=0

=> 2x-12=0

=> 2x= +12

=> x= +6.

Therefore the Oxidation number of Cr in the given compound is +6.


  • 10

Its +6

  • -2

goood copying work...

  • -4

hiiiiiiiiiiiiii

W. K. T Oxidation no of Oxygen= -2

and oxidation no of potassium= +1

so let us take the oxidation no of cromium as 'x'

so,

  +2+2x-14=0(since charge on oxygen is 0 becoz a free element has 0 charge on it)

  2x-12=0

  2x=+12

  x=+12/2

  x=+6

hence oxidation no of cromium is +6

hope this helps u!!!

keep smiling???

  • 22
What are you looking for?