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 Explain n(AuB) =n(A) +n(B)-n(A intersection B)?

Asked by somenath.saha1....(tutor) , on 4/11/10

Answers

n(AuB) =n(A)+n(B) minus n(A intersection B)

suppose,A={1,2,3,4}  B={4,5,6,7}

thus,(AuB)={1,2,3,4,5,6,7}   and (A intersection B)={4}

n(A)=4  n(B)=4  n(AuB)=7  n(A intersection  B)=1

therefore,7=4+4-1=7

hence proved that,n(AuB)=n(A)+n(B)-n(A intersection B) 

Posted by Srijan Gupta(student)on 8/11/10

EXPERT ANSWER
Hi Somenath!
The relation given you can be explained as,
Using this relation, you can solve various problems.
 

Cheers!

Posted by Sunanta Meitei(MeritNation Expert)on 12/11/10

This conversation is already closed by Expert

EXACTLY WHAT MERIT NATION EXPERT SAID

Posted by Mihir Bagchi(student)on 23/8/11

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