#### Answers

n(AuB) =n(A)+n(B) minus n(A intersection B)

suppose,A={1,2,3,4} B={4,5,6,7}

thus,(AuB)={1,2,3,4,5,6,7} and (A intersection B)={4}

n(A)=4 n(B)=4 n(AuB)=7 n(A intersection B)=1

therefore,7=4+4-1=7

hence proved that,n(AuB)=n(A)+n(B)-n(A intersection B)

Posted by Srijan Gupta(student), on 8/11/10

EXPERT ANSWER

Hi Somenath!

The relation given you can be explained as,

Using this relation, you can solve various problems.

Cheers!

Posted by Sunanta Meitei(MeritNation Expert), on 12/11/10

This conversation is already closed by Expert

EXACTLY WHAT MERIT NATION EXPERT SAID

Posted by Mihir Bagchi(student), on 23/8/11

Ask a QuestionHave a doubt? Ask our expert and get quick answers.

Show me more questions