factorise 16x3 - 250y3

16x3-250y3= 28x3-125y3= 22x3-5y3= 22x-5y2x2+2x×5y+5y2 {using the identity a3-b3= a-ba2+ab+b2} = 22x-5y4x2+10xy+25y2

factorise 16x³ - 250y³

16 x^{3} - 250 y^{3} = 2 [8 x^{3} - 125 y^{3}] = 2 [{(2 x)}^{3} - {(5 y)}^{3}] = 2 [2 x - 5 y] [{(2 x)}^{2} + 2 x \times 5 y + {(5 y)}^{2}] {using the identity a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})} = 2 (2 x - 5 y) (4 x^{2} + 10 x y + 25 y^{2})