factorise: 27a3+ 1/64b3+27a2/4b +9a/16b2 Share with your friends Share 1 Pooja Khanna answered this Here is the link for the answer to your query: https://www.meritnation.com/ask-answer/question/factorise-27a3-1-64b3-27a3-4b-9a-16b2/math/2949836 0 View Full Answer Swagat Swargari answered this Using identity: (a + b)3 = a3 + b3 + 3ab(a+b) 27a3 + 1/64b3 + 27a2/4b + 9a/16b2 = (3a)3 + (1/4b)3 + 3*3a*(1/4b) (3a + 1/4b) = (3a + 1/4b)3 = (3a + 1/4b)(3a + 1/4b)(3a + 1/4b) 7
