factorise : (x + 1)(x + 2)(x + 3)(x + 4) - 3 Share with your friends Share 2 Anuradha Sharma answered this Rearranging the given expression asx+1x+4x+2x+3-3=0x2+5x+4x2+5x+6-3=0Let x2+5x= t t+4t+6-3=0t2+10t+21=0t2+7t+3t+21=0tt+7+3t+7=0t+7t+3=0t = -7,-3 x2+5x+7=0 or x2+5x+3=0x2+5x+7=0Here D = 25-28 = -3<0 so it cannot be factorize or x2+5x+3=0Using quadratic formula, x = -5±25-122=-5±132So the factors are x--5+132x--5-132 0 View Full Answer
