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factorise (x2 -3x)2 -8 )x2-3x)-20

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let x2-3x be a

a2 - 8a - 20

a2 -10a + 2a -20 (by splitting the middle term)

a(a-10) + 2(a-10)

(a-10)(a+2)

now put the value of a

[(x2-3x)-10]*[(x2-3x)+2]

[x(x-3)-10] [x(x-3)+2]

[x(x-3-10)] [x(x-3+2)]

x(x-13) * x(x-1)

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