factorise : x4 +4
 

  • 0
X4+4
 = X4+4+4X2-4X2
   =(X2)2+(2)2 +(2.2.X2) - (2X)2
     =  (X2+2)2-(2X)2
       =   (X2+2+2X)(X2+2-2X)
  • 3
x4+4can be written as (x2)2+(2)2
let we use the identity
a2+b2=a2+2ab+b2
=x2+2(x2)(2)+(2)2
=x2(1+2)+2(1+2)
=(1+2)(x2+2)
  • 1
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