factorize a^3+3a^2b+3ab^3+b^3 without using identities
Answer :
We have : a3 + 3a2b + 3ab2 + b3 , So
= a3 + 2 a2b + a2b + 3ab2 + ab2 + b3
= ( a3 + 2 a2b + ab2 ) + ( a2b + 3ab2 + b3 )
= a ( a2 + 2ab + b2 ) + b ( a2 + 2ab + b2 )
= ( a + b ) ( a2 + 2ab + b2 )
= ( a + b ) [ a2 + ab + ab + b2 ]
= ( a + b ) [ a ( a + b ) + b ( a + b ) ]
= ( a + b ) ( a + b ) ( a + b )
= ( a + b )3 ( Ans )
We have : a3 + 3a2b + 3ab2 + b3 , So
= a3 + 2 a2b + a2b + 3ab2 + ab2 + b3
= ( a3 + 2 a2b + ab2 ) + ( a2b + 3ab2 + b3 )
= a ( a2 + 2ab + b2 ) + b ( a2 + 2ab + b2 )
= ( a + b ) ( a2 + 2ab + b2 )
= ( a + b ) [ a2 + ab + ab + b2 ]
= ( a + b ) [ a ( a + b ) + b ( a + b ) ]
= ( a + b ) ( a + b ) ( a + b )
= ( a + b )3 ( Ans )