Find dy/dx; If y=tan-1(2x/1+15x2) Share with your friends Share 2 Manbar Singh answered this Let y = tan-12x1 + 15x2⇒y = tan-15x - 3x1 + 5x . 3xput 5x = tan α ; 3x = tan βNow, y = tan-1tan α - tan β1 + tan α . tan β⇒y = tan-1tanα - β⇒y = α - β⇒y = tan-15x - tan-13x⇒dydx = 11 + 25x2 × 5 - 11 + 9x2 × 3⇒dydx = 51 + 25x2 - 31 + 9x2 14 View Full Answer Adithya Krishna answered this y=tan-1(2x/1+5x2) y=tan-1(5x-3x/1+5x.3x) Put 5x=tanA and 3x=tanB; Now, y=tan-1(tanA-tanB/1+tanAtanB) y=tan-1(tan(A-B)) y=A-B y=tan-15x-tan-13x dy/dx=5.1/1+(5x)2 - 3.1/1+(3x)2 . . . dy/dx=5/1+25x2 - 3/1+9x2 0
