Find dy/dx, when: x sin 2y = y cos 2x The answer: ( 2 y sin 2x + sin 2y ) / ( cos 2x - 2 x cos 2y ) Share with your friends Share 2 Varun.Rawat answered this We have,x sin 2y = y cos 2xdifferentiating both sides with respect to x, we getx × 2 cos 2ydydx + sin 2y × 1 = y × - 2sin 2x + cos 2x × dydx⇒2x cos 2ydydx - cos 2xdydx = - 2y sin 2x - sin 2y⇒dydx2x cos 2y - cos 2x = -2 y sin 2x + sin 2y⇒dydx =-2 y sin 2x + sin 2y2x cos 2y - cos 2x⇒dydx = 2y sin 2x + sin 2ycos 2x - 2x cos 2y 4 View Full Answer
