find sum of all ODD numbers between 0 and 50.

1st odd no.=1
last odd no.=49

a=1, an or l=49, common diff. d= 2,

an=a+(n-1)d

=1+(n-1)2=49

=1+2n-2=49

=2n-1=49

=2n=49=1

=2n=50

n=25

sn=n/2(a+l)

=25/2(1+49)

=25/2 * 50

=25*25=625

therefore sum of all odd integers between 0 to 50 is 625 :D

 

 

 

 

 

 

 

m of odd nos. btwn 0-50 is 625 :)

  • 25

first odd no is 1 and last odd no is 49 and difference between 2 consecutive odd no. is 2 by using arithmetic progression there are 25odd no 0to50 found by tn=a+(n-1)d where a=1 and tn=49
Sn=25/2(a+tn)
=25/2(1+49)
=25*25
=625
Thus the sum of odd no. from1 to 50 is 625

  • 8

 1st odd no.=1
last odd no.=49

a=1,  an or l=49, common diff. d= 2, 

an=a+(n-1)d

=1+(n-1)2=49

=1+2n-2=49

=2n-1=49

=2n=49=1

=2n=50

n=25

sn=n/2(a+l)

=25/2(1+49)

=25/2 * 50

=25*25=625

therefore sum of odd nos. btwn 0-50 is 625 :)

  • 4
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