Find the area of a quadrant of a circle whose circumference is 22 cm. Take PIE= 22/7

 circumference of circle = 22 cm

therefore  2 pi r = 22

r = 22 x 7 / 2 x 22

on cancellation

r = 7 / 2 = 3.5 cm

therfore area of quadrant = pi r square / 4

                                              = 22 / 7 x 3.5 x 3.5 x 1 / 4

                                              = 38.5 / 4 cm square = 9.625 cm square

Circumference of a quadrant is 1/4 the circumference so the circumference of the circle is 4x22=88cm, Also circumference of a circle is 2(pi)R.

=>2x22/7xR=88cm

 >R=88x7/22x2

 >R=88x7/44

 >R=2x7

 >R=14cm

 2πr =22

R= 22 *7/22 *1/2

So r= 7/2

Now area of quadrant = πr²ϴ/360

22/7*49/4*90/360

So area of quadrant=9.6250

circumference = 2*pi*r

22 = 2 * 22/7 * r

r = 22 * 7/22 * 1/2

r = 7/2 cm

area of quadrant = 1/4 * pi * r * r

= 1/4 * 22/7 * 7/2 * 7/2

= 77/8 cm sq.

circumference of circle= 2 XpieXr

22= 2X(22/7)Xr

(22X7)/(22X2)=r

7/2=r

area of quadrant= 1/4X pie X r^2

=(1/4)X(22/7)X(7/2)^2

=77/8