circumference of circle = 22 cm therefore 2 pi r = 22 r = 22 x 7 / 2 x 22 on cancellation r = 7 / 2 = 3.5 cm therfore area of quadrant = pi r square / 4 = 22 / 7 x 3.5 x 3.5 x 1 / 4 = 38.5 / 4 cm square = 9.625 cm square Posted by Divya Janjua(student)on 6/3/13

circumference of circle = 22 cm therefore 2 pi r = 22 r = 22 x 7 / 2 x 22 on cancellation r = 7 / 2 = 3.5 cm therfore area of quadrant = pi r square / 4 = 22 / 7 x 3.5 x 3.5 x 1 / 4 = 38.5 / 4 cm square = 9.625 cm square Posted by Divya Janjua(student)on 6/3/13

circumference of circle = 22 cm therefore 2 pi r = 22 r = 22 x 7 / 2 x 22 on cancellation r = 7 / 2 = 3.5 cm therfore area of quadrant = pi r square / 4 = 22 / 7 x 3.5 x 3.5 x 1 / 4 = 38.5 / 4 cm square = 9.625 cm square Posted by Divya Janjua(student)on 6/3/13

Circumference of a quadrant is 1/4 the circumference so the circumference of the circle is 4x22=88cm, Also circumference of a circle is 2(pi)R. =>2x22/7xR=88cm >R=88x7/22x2 >R=88x7/44 >R=2x7 >R=14cm Posted by Namrata Chhabra(student)on 6/3/13

Circumference of a quadrant is 1/4 the circumference so the circumference of the circle is 4x22=88cm, Also circumference of a circle is 2(pi)R. =>2x22/7xR=88cm >R=88x7/22x2 >R=88x7/44 >R=2x7 >R=14cm Posted by Namrata Chhabra(student)on 6/3/13

Circumference of a quadrant is 1/4 the circumference so the circumference of the circle is 4x22=88cm, Also circumference of a circle is 2(pi)R. =>2x22/7xR=88cm >R=88x7/22x2 >R=88x7/44 >R=2x7 >R=14cm Posted by Namrata Chhabra(student)on 6/3/13

2 π r =22 R= 22 *7/22 *1/2 So r= 7/2 Now area of quadrant = π r² ϴ /360 22/7*49/4*90/360 So area of quadrant=9.6250 Posted by Mohammed Meeran(student)on 6/3/13

2 π r =22 R= 22 *7/22 *1/2 So r= 7/2 Now area of quadrant = π r² ϴ /360 22/7*49/4*90/360 So area of quadrant=9.6250 Posted by Mohammed Meeran(student)on 6/3/13

2 π r =22 R= 22 *7/22 *1/2 So r= 7/2 Now area of quadrant = π r² ϴ /360 22/7*49/4*90/360 So area of quadrant=9.6250 Posted by Mohammed Meeran(student)on 6/3/13

circumference = 2*pi*r 22 = 2 * 22/7 * r r = 22 * 7/22 * 1/2 r = 7/2 cm area of quadrant = 1/4 * pi * r * r = 1/4 * 22/7 * 7/2 * 7/2 = 77/8 cm sq. Posted by Nimrat Kaur(parent)on 6/3/13

circumference = 2*pi*r 22 = 2 * 22/7 * r r = 22 * 7/22 * 1/2 r = 7/2 cm area of quadrant = 1/4 * pi * r * r = 1/4 * 22/7 * 7/2 * 7/2 = 77/8 cm sq. Posted by Nimrat Kaur(parent)on 6/3/13

circumference = 2*pi*r 22 = 2 * 22/7 * r r = 22 * 7/22 * 1/2 r = 7/2 cm area of quadrant = 1/4 * pi * r * r = 1/4 * 22/7 * 7/2 * 7/2 = 77/8 cm sq. Posted by Nimrat Kaur(parent)on 6/3/13

circumference of circle= 2 XpieXr 22= 2X(22/7)Xr (22X7)/(22X2)=r 7/2=r area of quadrant= 1/4X pie X r^2 =(1/4)X(22/7)X(7/2)^2 =77/8 Posted by Rittul Arya(student)on 6/3/13

circumference of circle= 2 XpieXr 22= 2X(22/7)Xr (22X7)/(22X2)=r 7/2=r area of quadrant= 1/4X pie X r^2 =(1/4)X(22/7)X(7/2)^2 =77/8 Posted by Rittul Arya(student)on 6/3/13

circumference of circle= 2 XpieXr 22= 2X(22/7)Xr (22X7)/(22X2)=r 7/2=r area of quadrant= 1/4X pie X r^2 =(1/4)X(22/7)X(7/2)^2 =77/8 Posted by Rittul Arya(student)on 6/3/13

as u knw circumference of a circle = 2 * pie * radius, 22 = 2 * 22/7 * r , r = 7/2 area of circle = 1/4 * pie * radius * radius = 1/4 * 22/7 * 7/2 * 7/2 = 77/8 ans Posted by Sweety Purnima ...(student)on 31/10/14

as u knw circumference of a circle = 2 * pie * radius, 22 = 2 * 22/7 * r , r = 7/2 area of circle = 1/4 * pie * radius * radius = 1/4 * 22/7 * 7/2 * 7/2 = 77/8 ans Posted by Sweety Purnima ...(student)on 31/10/14

as u knw circumference of a circle = 2 * pie * radius, 22 = 2 * 22/7 * r , r = 7/2 area of circle = 1/4 * pie * radius * radius = 1/4 * 22/7 * 7/2 * 7/2 = 77/8 ans Posted by Sweety Purnima ...(student)on 31/10/14