The diagonals of a parallelogram bisect each other. Here the point of intersection would be the point of bisection as well. That means if we calculate the mid points of the diagonals. It should be equal and same.
Let the given coordinates be the coordinates of a parallelogram ABCD. We will calculate the Mid points of DIagonal AC and BD. They should be same.
Mid points of a line segmant = (X1+X2) / 2 , (Y1+Y2) / 2
Mid points of diagonal AC = (-2+4) / 2 , (-1+3) / 2
The mid points are (1,1)
Mid points of Diagonal BD = (1+1) / 2 , (0+2) / 2
So the mid points of DIagonal BD = (1,1)
Both the mid points are same. Though the question is not complete and Clear but I hope that this is the answer you are looking for.