find the flux through the surface of a equillateral cone.


Here, the flux is equal to the product of the magnitude of the field and the total surface area. The flux will be given by,
Electric flux=Electric field x Area
Surface area of cone is given by,
πr(l+r)For equilateral cone  side or slant height 'l' is equal to the diameter of the base.i.e. l=2rSo, A=π r(2r+r)=3r×πr=3πr2Thus,Flux, ϕ=E×3πr2

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1 week 3 days ago
and still no answer!
plz helpppp


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